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--- bash:command_line_arguments [2019/12/12 20:45] – [Getting Arguments with Names] peter
+++ bash:command_line_arguments [2021/01/26 16:56] (current) – removed peter
@@ Line 1: / Line 1: @@
-====== BASH - Command Line Arguments ======
-Getting arguments directly from the command shell can be beneficial in a number of cases.
-<code bash>
-#!/bin/bash
-echo "Total arguments : $#"
-echo "First Argument = $1"
-echo "Second Argument = $2"
-</code>
-Run this script with two additional parameters after its name.
-I’ve named it test.sh and the calling procedure is outlined below.
-<code bash>
-./test.sh Hello Peter
-</code>
-$1 is used for accessing the first argument, $2 for the second, and so on.
-The $# is used for getting the total number of arguments.
-----
-===== Getting Arguments with Names =====
-The below example shows how to get command-line arguments with their names.
-<code bash>
-#!/bin/bash
-for arg in "$@"
-do
-index=$(echo $arg | cut -f1 -d=)
-val=$(echo $arg | cut -f2 -d=)
-case $index in
-X) x=$val;;
-Y) y=$val;;
-*)
-esac
-done
-((result=x+y))
-echo "X+Y=$result"
-</code>
-Name this script test.sh and call it as shown below.
-<code bash>
-./test.sh X=44 Y=100
-</code>
-It should return X+Y=144.
-The arguments here are stored inside ‘$@‘ and the script fetches them using the Linux cut command.